Handling JSON Request and Response

Note: I have Explained this in Spring Please Modify The Accordingly.

HTML Page

<div class="signIn-box">
    <form  id="UserLoginForm" method="post" action="javascript:void(0);">
        <div style="display:none;">
<input type="hidden" id ="loginaction" name="action" value="${hosturi}application/login.htm">
</div>
    <label>User Name:</label>
        <input name="loginUsername" type="text"  maxlength="15" id="UserUsername">
        <label>Password:</label>
        <input type="password" name="loginPassword" id="UserPassword">

         <input type="submit" name="login" id="login" value="LOGIN" onclick="return submitLogin();"/>
      </form>
</div>

<span id="status"></span>
<span id="userdata"></span>

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Script

function submitLogin(){

// Gets The Form Data and Stores in the Variable
var postData = $('#UserLoginForm').serialize();

// gets the URL to Submit the Form Data
   var formURL = $('#loginaction').val();

   $.ajax({
       url : formURL,

//Type of Method to Submit the Form Data
       type: "POST",
       data : postData,
     
// Form Data Response Handler
       success:function(responseText){
        if(responseText.status == 'success'){
       
var user = responseText.uservo;

var userMsg = 'Hi ' + user.getUserName + ' your password is ' + user.getPassword + ' Thank you ';

        $('#status').html("Logged In");
        $('#userdata').append(userMsg);

        }else if(responseText.status == 'notActivated'){
        $('#loginmessages').html("<span style='font-size:12px;'>Your account is not activated. Please click on the link sent to your registered email and activate your account</span>");
          }
       },
       error: function(jqXHR, textStatus, errorThrown){
alert('enter valid credentials');
        unblock();
       }
   });
}

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Spring Controller Class

@RequestMapping(value = "login", method = RequestMethod.POST)
public String login(HttpServletRequest request, HttpServletResponse response, Model model){
userService.getUser(request,response,model);
response.setContentType("application/json");
        return "jsonView";

}

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Spring Service Class

@Transactional
public void getUser(HttpServletRequest request,HttpServletResponse response, Model model){

String userName = request.getParameter("loginUsername");
String password = request.getParameter("loginPassword");
if(userName != null && !userName.isEmpty() && password != null && !password.isEmpty()){

// Write the code connect to database and check the user in the database and password are matched

UserVO uservo = new UserVO();
uservo.setUserName(userName);
uservo.setUserPassword(password);

model.addAttribute("status", "success");
model.addAttribute("uservo", uservo);

}else{
model.addAttribute("status", "required");
}

}

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